Question

factorise the following polynomial no spam or i will report​

Answer 1

Answer:

The factors are

(x,x,x), (x,x,x,x,x,x), (3,x), (-7)

Step-by-step explanation:

X^3 = x*x*x

3x^2 =3x*3x= x*x*x*x*x*x

3x= x*3

-7= (-7)

factors are=(x,x,x), (x,x,x,x,x,x), (3,x), (-7)

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Answer 2

Answer:

( x - 1 ) ( x square + 4x + 7)

Step-by-step explanation:

First step is find at least one factor of the equation which satisfies the equation. Normally hit-and-trial method can be used by using -2, -1 ,0, 1 , 2 by putting value for x. If the function values zero then it is the factor.

Here I found 1 as the factor

Step 2 is to divide the equation by ( x minus factor) to get other equation which subsequently gives remaining factor.

In your equation the next equation we get is a quadratic with non real roots so there is no further factorisation. But note that if you try this method on another equation which can be factorised further, do the factorisation to make it easy. All the Best