Question

factorise the following polynomials (3a-1)^2-6a+2​

Answer 1

$\huge{Hey ! \ Dude}$

Here is your answer

(3a-1)^2-6a+2​

9a^2-6a+1-6a+2 
9a^2-12a+3 
3(3a^2-4a+1) 
3(3a-1)(a-1)

Hope its help you

Answer 2

$(3a - 1) {}^{2} - 6a + 2 \\ (3a - 1) {}^{2} - 2(3a - 1) \\( 3a - 1)(3a - 1 - 2)$