Question

factorise the following polynomials
this is the question and please help me to solve this ​

Answer 1

$\: \: \: \: \: {(3a - 1)}^{2} - 6a + 2 \\ = {(3a)}^{2} - 2(3a)(1) + {(1)}^{2} - 6a + 2 \\ = 9 {a}^{2} - 6a + 1 - 6a + 2 \\ = 9 {a}^{2} - 12a + 3$

= 9a² - 9a - 3a + 3

= 9a(a - 1) -3(a - 1)

= (9a - 3)(a - 1)

Answer 2

Answer:

9a sq. +1 -6 a -6a +2

9a sq.-12a+3

9a sq. -9a-3a+3

9a ( a -1)-3 (a-1)

(a-1)(9a-3)