Question

factorise the following quadratic equation by factorisation 9x^2-6b^2x-(a^4-b^4)=0

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Answer 1

Step-by-step explanation:

Given: 9x2−6b2x−(a4−b4)=09x2−6b2x−(a4−b4)=0 To find: The value of above equation. Solution: In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized. We know: a2 - b2 = (a + b)(a - b) Consider, 9x2−6b2x−(a4−b4)=09x2−6b2x−(a4−b4)=0 Here, apply the above formula and solve, ⇒ 9x2 – 3(a2 + b2)x + 3(a2 – b2)x – (a2 + b2)(a2 – b2) = 0 ⇒ 3x(3x – (a2 + b2)) + (a2 – b2)(3x – (a2 + b2)) = 0 ⇒ (3x + a2 – b2)(3x – (a2 + b2) = 0 ⇒ x =b2−a23,a2+b23=b2−a23,a2+b23Read more on Sarthaks.com - https://www.sarthaks.com/1077431/solve-the-following-quadratic-equations-by-factorization-9x-2-6b-2x-a-4-b-4-0