factorise the following quadratic expression 1-2a-3a²
Answers
Answered by
28
-(3a²+2a-1)
= - (3a²+3a-a-1)
= -3a(a+1)-1(a+1)
= -(3a+1)(a+1)
= - (3a²+3a-a-1)
= -3a(a+1)-1(a+1)
= -(3a+1)(a+1)
Answered by
14
SOLUTION:-
1-2a -3a^2
= -(3a^2+2a-1)
= -[3a^2+3a-a-1]
= -[ 3a(a+1) -1(a+1)]
= -[(a+1)(3a-1)]ans
1-2a -3a^2
= -(3a^2+2a-1)
= -[3a^2+3a-a-1]
= -[ 3a(a+1) -1(a+1)]
= -[(a+1)(3a-1)]ans
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