Math, asked by princenon, 1 year ago

factorise the following quadratic expression 1-2a-3a²

Answers

Answered by priyanshikarn48

3

-3a²-2a+1
-3a²-3a+a+1
-3a(a+1)+1(a+1)
(-3a+1)(a+1)
a=1/3,-1

Answered by Anonymous

4

-2a -3a^2

= -(3a^2+2a-1)

= -[3a^2+3a-a-1]

= -[ 3a(a+1) -1(a+1)]

= -[(a+1)(3a-1)]ans

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