factorise the following question :81p^2-16
Answers
Answered by
3
=>81p^2-16
=>(9p)^2 -(4)^2
since [(a^2-b^2=(a+b)(a-b)]
=>(9p+4)(9p-4)------(answer)
hope it helps!!
=>(9p)^2 -(4)^2
since [(a^2-b^2=(a+b)(a-b)]
=>(9p+4)(9p-4)------(answer)
hope it helps!!
Answered by
2
81p^2 -16
81p^2 = 16
p^2 = 16/81
p = + 4/9 or p = -4/9
so the factors are (p + 4/9) and (p - 4/9)
or (9p + 4) (9p - 4)
81p^2 = 16
p^2 = 16/81
p = + 4/9 or p = -4/9
so the factors are (p + 4/9) and (p - 4/9)
or (9p + 4) (9p - 4)
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