Question

factorise the following question
p3-3p2+2p-6-pq+3q​

Answer 1

$\huge \bold \pink{solution}$

$p(3) - 3p(2) + 2p - 6 - pq + 3q$

$\mathtt \longrightarrow \: 3p - 6p + 2p - 6 - pq + 3q$

$\mathtt \longrightarrow \: 5p - 6p - 6 - pq + 3q$

$\mathtt \longrightarrow \: - p - 6 - pq + 3q$

Answer 2

Step-by-step explanation:

=[p³- 3p²] + [2p-6)+(-pq+3q)

=p² (p - 3) + 2p-3) - q (p - 3)

= (p-3) ( p²+2q) Ans

hope it is useful to you ☺️