Math, asked by dev091205, 10 months ago

factorise the following questions
x^2-3x+3y-y^2

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Answered by BrainlyKing111

1

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HERE IS THE ANSWER....

x^2-3x+3y-y^2

=(x+y)(x-y)-3(x+y) [(a+b)(a-b)=a^2-b^2]

=(x+y) and (-3x+3y) are the factors....

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