Question

factorise the following sum 343a³-64b³​

Answer 1

$\bold{ 343a³-64b³}$

$\bold{{a}^{3} - {b}^{3} = (a + b)( {a}^{2} + ab + {b}^{2} ) }$

$\bold{where \: a = 7a \: and \: b = 4b}$

$\bold{(7a - 4b)(49 {a}^{2} + 28ab + 16b {}^{2} )}$

Answer 2

Answer:

$\huge\sf{\purple{\fbox{\pink{\fbox{\purple{\fbox{\pink{Answer}}}}}}}}$

$(7a - 4b) \times (49a + 28ab + 16b^{2} )$

hope it helps