Question

Factorise the following :t^2-4 and x^2-36

Answer 1

Answer:

$\red {t^{2} - 4} \green {=(t+2)(t-2)}$

$\red {x^{2} - 36}\green {= (x+6)(x-6)}$

Step-by-step explanation:

$\boxed {\pink { (a^{2} - b^{2} = (a+b)(a-b)}}$

$i) t^{2} - 4 \\= t^{2} - 2^{2}\\= (t+2)(t-2)$

$ii) x^{2} - 36 \\= x^{2} - 6^{2}\\= (x+6)(x-6)$

Therefore.,

$\red {t^{2} - 4} \green {=(t+2)(t-2)}$

$\red {x^{2} - 36}\green {= (x+6)(x-6)}$

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