factorise the following terms 8a³-12a²b+6ab²-b³
Answers
Answered by
0
Answer:
8a^3-12a^2b+6ab^2-b^3
=(2a)^3-3.(2a)^2.b+3.(2a).b^2-(b)^3
=(2a-b)^3
Answered by
1
Step-by-step explanation:
8a³-b³-12a²b+6ab²
=(2a-b)(4a²+2ab+b²)-6ab(2a-b)
=(2a-b)(4a²+2ab+b²-6ab)
=(2a-b)(4a²-4ab+b²)
=(2a-b){(2a)²-2×2a×b+(b)²}
=(2a-b)(2a-b)²
=(2a-b)(2a-b)(2a-b)
Similar questions