Question

factorise the following:

${y}^{2} - 10x + 25$
${a}^{2} + 12a + 36$
​

Answer 1

Step-by-step explanation:

in first question it should be X instead of y

x²-10x+25= ( x-5)²

a²+12a+36= ( a+6)²

Hope it helps

Answer 2

Step-by-step explanation:

question :-

1)y2 +10x+ 25

2)a2+12a+36

1)ans:-y2+(5x)2+25 {(a2+b2+2ab)}

the answer is a=y and b=25

={(y+5)}2

=(y+5). (y+5)

2)ans:-a2+12a+36{(a2+b2+2ab)}

the answer is a=and b=36

={(a+6)}2

(a+6). (a+6)

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