Question

factorise the following trinomials
14x^2-23x+8
Please Help Me​

Answer 1

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$\implies\sf {14x}^{2} - 23x + 8 = 0$

$\implies\sf {14x}^{2} - 16x - 7x + 8 = 0$

$\implies\sf2x(7x - 8) - 1(7x - 8) = 0$

$\implies\sf(2x - 1) = 0 \: \: or \: \: (7x - 8) = 0$

$\implies\sf2x = 1 \: \: or \: \: 7x = 8$

$\implies\sf \: x = \dfrac{1}{2} \: \: or \: \: x = \dfrac{8}{7}$

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