Question

factorise the following trinomials b^2+2b+1​

Answer 1

Answer:

(b+1)^2

Step-by-step explanation:

→b^2+2b+1

=b^2+2(1)(b)+1^2→equation (1)

a=b,b=1

• the equation (1) is in the form of a^2+b^2+2ab=(a+b)^2,where a=b and b=1.

so,b^2+2b+1 =(b+1)^2

hence,(b+1)^2 is the solution.

I HOPE IT HELPS YOU

Answer 2

Answer:

(b+1)²

step-by-step answer:

b² + 2b + 1

Rewrite 1 as 1²

b² + 26 + 1²

Check the middle term by multiplying 2ab and compare this result with the middle term in the original expression.

2ab = 2. b. 1

Simplify.

2ab = 26 =

Factor using the perfect square trinomial rule

a² + 2ab + b = (a + b)², where a = b and b = 1.

(b+1)²