factorise the following using a p p r o p r i a t e identities 9/16 x2 - y2/9
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Answered by
24
Step-by-step explanation:
(9/16 x^2 -y^2/9)
= (9x^2/16)-(y^2/9)
= [(3x/4)^2] - [(y/3)^2].
= [(3x/4) -(y/3)] [(3x/4)+(y/3)]
(using a^2 - b^2 = (a-b) (a+b)
Answered by
3
4x2-8xy-y2 I think Soo.
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