Question

factorise the following using a suitable identity 4y²+4y+1​

Answer 1

Answer:

Given Quadratic Expression is :

${4y}^{2} - 4y + 1$

$= ( {2y})^{2} - 2 \times 2y \times 1 + {1}^{2}$

$= ( 2y - {1})^{2}$

[ By algebraic identity

${a}^{2} - 2ab + {b}^{2} = (a - {b})^{2}$

$= (2y - 1)(2y - 1)$