factorise the following using appropriate identifies (i) 9x² + 6xy + y² , (ii) 4y² - 4y + 1 , (iii) x² - y²/100
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Answered by
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(i) 9x² + 9xy + y²
[ using : (a+b)² = a² + 2ab + b² ]
Here,
a = 3x , b = y
So,
=> (3x)² + 2*3x*y + (y)²
=> (3x + y)²
=> (3x + y) (3x + y)
➖➖➖➖➖➖➖➖➖➖
(ii) 4y² - 4y + 1
[using : (a - b)² = a² - 2ab + b² ]
Here,
a = 2y , b = 1
So,
=> (2y)² / 2*2y*1 + (1)²
=> (2y - 1)²
=> (2y - 1) (2y - 1)
➖➖➖➖➖➖➖➖➖➖
(iii) x² - y²/100
[ using : a² - b² = (a+b) (a-b)
Answered by
64
:
(i) 9x² + 9xy + y²
[ using : (a+b)² = a² + 2ab + b² ]
Here,
a = 3x , b = y
So,
=> (3x)² + 2*3x*y + (y)²
=> (3x + y)²
=> (3x + y) (3x + y)
➖➖➖➖➖➖➖➖➖➖
(ii) 4y² - 4y + 1
[using : (a - b)² = a² - 2ab + b² ]
Here,
a = 2y , b = 1
So,
=> (2y)² / 2*2y*1 + (1)²
=> (2y - 1)²
=> (2y - 1) (2y - 1)
➖➖➖➖➖➖➖➖➖➖
(iii) x² - y²/100
[ using : a² - b² = (a+b) (a-b) ]
Here,
a = x
b =
So,
(i) 9x² + 9xy + y²
[ using : (a+b)² = a² + 2ab + b² ]
Here,
a = 3x , b = y
So,
=> (3x)² + 2*3x*y + (y)²
=> (3x + y)²
=> (3x + y) (3x + y)
➖➖➖➖➖➖➖➖➖➖
(ii) 4y² - 4y + 1
[using : (a - b)² = a² - 2ab + b² ]
Here,
a = 2y , b = 1
So,
=> (2y)² / 2*2y*1 + (1)²
=> (2y - 1)²
=> (2y - 1) (2y - 1)
➖➖➖➖➖➖➖➖➖➖
(iii) x² - y²/100
[ using : a² - b² = (a+b) (a-b) ]
Here,
a = x
b =
So,
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