Question

factorise the following using appropriate identities 49a square +70ab + 25b square​

Answer 1

Answer:

• 7a)^2+2×71×5b+(5b)^3
• (7a+5b)^2
• (a+b)^2=a^2+b^2+2ab

Answer 2

Answer:it's (7a+5b)^2

Step-by-step explanation:

Break the above equation as

a^2 + 2ab + b^2

Now we can do this as

(7a)^2 + 2 * 7a * 5b + (5b) ^2

After breaking it we can rewrite it as

(7a+5b) ^2

Hope you get the appropriate answer

Thanks

Feel free to ask your query