Question

factorise the following using appropriate identities: 4y²- 4y +1......

Answer 1

Here equation=

$4y {}^{2} - 4y + 1$

It can be solved by using identity

(A-B)^2=A^2-2AB+B^2

$(2y) {}^{2} - 2(2y)(1) + 1 { }^{2} \\ (2y - 1) {}^{2}$

Answer 2

Answer:

hey mate

here is ur answer

4y²-4y+1

the identity used in this equation is

(a-b)²= a²+ b²-2ab

so, 4y² +1- 4y

(2y)² + (1)² - (2* 2y * 1)

so, by factorising it we got

we get,. (2y+1)²

hope it helps u

pleasure to help you