Question

Factorise the following using appropriate identity: i) x² - 2x - 15
ii) x²-1x-5
3.) x²-7x+12
iv) x² -1x - 56
v) x² + 8x + 12
vi) x² + 1x - 5
vii) x² + 9x + 20
viii) x² - 2x - 63
please help​

Answer 1

Answer:

i) x² - 2x - 15

Answer = (x+3) , (x-5)

Step-by-step explanation:

Use the sum-product pattern

2−2−15

x^{2}{\color{#c92786}{-2x}}-15x2−2x−15

2+3−5−15

Common factor from the two pairs

2+3−5−15

x^{2}+3x-5x-15x2+3x−5x−15

(+3)−5(+3)

Rewrite in factored form

(+3)−5(+3)

x(x+3)-5(x+3)x(x+3)−5(x+3)

(−5)(+3)