Question

Factorise the following using approximate identities (1)t^2-2t+1

Answer 1

Given that,

${t}^{2} - 2t + 1 = 0 \\ ⟹ {t}^{2} - t - t + 1 = 0 \\ ⟹t(t - 1) - 1(t - 1) = 0 \\ ⟹(t - 1)(t - 1) = 0 \\ ⟹t - 1 = 0; \: t - 1 = 0 \\ ⟹t = 0 + 1; \: t = 0 + 1 \\ ⟹t = 1 ;\: t = 1$

Therefore, t = 1

Step-by-step explanation:

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