Question

Factorise the following using identities 9+6p +p^2

Answer 1

$\huge\underline\frak\green{Solution}$

${p^2+6p+9}$

${p^2+3p+3p+9}$

${p(p+3)+3(p+3)}$

${(p+3)(p+4)}$

Answer 2

Answer:

P= -3

Step-by-step explanation:

P^2 +6P+9

=(P^2 + 3P)(+3P+9)

=P(P+3)+3(P+9)

=(P+3)(P+3)

=P= -3

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