Question

Factorise the following using Identity
100b2_60bc+9c2​

Answer 1

Answer:

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Step-by-step explanation:

4a

2

+b

2

+c

2

−4ab+2bc−4ca

=(2a)

2

+(−b)

2

−(c)

2

−2(2a)(−b)+2(−b)(−c)+2(2a)(−b)

We know that x

2

+y

2

+z

2

+2xy+2yz+2xz=(x+y+z)

2

Here, x=2a, y=−b and z=−c

4a

2

+b

2

+c

2

−4ab+2bc−4ca

=(2a)

2

+(−b)

2

−(c)

2

−2(2a)(−b)+2(−b)(−c)+2(2a)(−b)

=(2a−b−c)

2

=(2a−b−c)(2a−b−c)