Question

Factorise the following using splitting the middle term method. Minimum one pls.

Answer 1

x² + 4√2 x + 6

=> x² + ( 3√2 + √2 )x + 6

=> x² + 3√2x + √2x + 6

=> x( x + 3√2 ) + √2( x + 3√2 )

=> ( x + 3√2 ) ( x + √2 )




( ii ) :


x² - 3√5x - 20

=> x² - ( 4√5 - √5 )x - 20

=> x² - 4√5x + √5x - 20

=> x( x - 4√5 ) + √5( x - 4√5 )


=> ( x - 4√5 ) ( x + √5 )





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