Question

factorise the following using suitable identities 1-8a³​

Answer 1

Answer:

(1-2a)(1-2a+4$a^2$)

Step-by-step explanation:

1 = $1^3$

8 = $2^3$

1 - 8$a^3$ = $1^3-(2a)^3$

$a^3-b^3 = (a-b)(a^2+ab+b^2)$

Hence, the answer is (1-2a)(1-2a+4$a^2$)

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