factorise the following using suitable identities 9a²–4b²–6a+1
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(3a^2 +1+6a) -(2b)^2 =(3a^6a)^2 -(2b)^2=(3a^2+6a+2b) (3a^2+6a-2b
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(3a-1+2b)(3a-1-2b)
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(9a^2-6a+1)-(4b^2) = (3a-1)^2 - (2b)^2 = (3a-1+2b)(3a-1-2b)
correct
find the following products by using suitable identities part 1 (2x+5) (2x-5)
place
(2x)^2-(5)^2 ==>4x^2 - 25 {a^2 - b^2 = (a+b) (a -b)
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