Question

factorise the following using suitable identities 9x^2+4y^2+25z^2+24xy-20yz-30zx​

Answer 1

$\huge{❥}\:{\mathtt{{\purple{\boxed{\tt{\pink{\red{A}\pink{n}\orange{s}\green{w}\blue{e}\purple{r᭄}}}}}}}}❥$

_______________________________________

${9x}^{2} - 24xy + {16y}^{2} \\ \\ ( {3x)}^{2} - 2 \times 3x \times ( - 4y) +({4y})^{2}$

This is in the form of (a - b)²

${a}^{2} - 2ab + {b}^{2} = (a - b)^{2} \\ (3x - 4y)(3x - 4y) \\(3x - 4y)^{2}$

(3x-4y)(3x-4y) This is the irreducable form.

_______________________________________

hope it helps you

have a great day ahead

Answer 2

Answer:

______________________________________

$\sf \: {9x}^{2} - 24xy + {16y}^{2}$

$\sf \red{( {3x)}^{2}} - 2 \times 3x \times ( - 4y) + \pink{({4y})^{2}}$

$\sf \: This \: is \: in \: the \: form \: of \pink{(a - b)²}$

$\sf{a}^{2} - 2ab + {b}^{2}$

$\sf =(a - b)^{2} (3x - 4y)(3x - 4y)(3x - 4y)^{2}$

$\sf \pink{(3x-4y)(3x-4y)} This \: is \: the \: \red{ irreducable \: form.}$

(3x-4y) (3x-4y) This is the irreducible form.