Factorise the following using suitable identities apower4-16bpower 4
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a⁴ - 16b⁴
We can also write this as :
⇒ (a²)² - (4b²)²
Identity : x² - y² = (x + y)(x - y)
Here, x = a², y = 4b²
⇒ (a² + 4b²)(a² - 4b²)
We can also write (a² - 4b²) as :
⇒ (a)² - (2b)²
Again using the above identity, we get
Here, x = a, y = 2b
⇒ (a + 2b)(a - 2b)
Hence, the answer is :
⏩ (a² + 4b²)(a + 2b)(a - 2b)
We can also write this as :
⇒ (a²)² - (4b²)²
Identity : x² - y² = (x + y)(x - y)
Here, x = a², y = 4b²
⇒ (a² + 4b²)(a² - 4b²)
We can also write (a² - 4b²) as :
⇒ (a)² - (2b)²
Again using the above identity, we get
Here, x = a, y = 2b
⇒ (a + 2b)(a - 2b)
Hence, the answer is :
⏩ (a² + 4b²)(a + 2b)(a - 2b)
Answered by
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Answer:
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Step-by-step explanation:
a⁴ - 16b⁴
We can also write this as :
⇒ (a²)² - (4b²)²
Identity : x² - y² = (x + y)(x - y)
Here, x = a², y = 4b²
⇒ (a² + 4b²)(a² - 4b²)
We can also write (a² - 4b²) as :
⇒ (a)² - (2b)²
Again using the above identity, we get
Here, x = a, y = 2b
⇒ (a + 2b)(a - 2b)
Hence, the answer is :
⏩ (a² + 4b²)(a + 2b)(a - 2b)
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