Factorise the following using suitable identities: x^2 – y^2 + 2x + 1
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Here's your answer
Given,
To factorise x² - y² + 2x + 1
Regrouping the terms,
we have ,
x² + 2x + 1 - y²
Using the identity (x+y)²=x² + 2xy + y²,
we have,
(x)² + 2(x)(1) + 1² - y²
(x + 1)² - y²
Using the identity , a² - b² = (a - b)(a + b)
x² - y² + 2x + 1 = (x + 1 - y)(x + 1 + y) [ Answer. ]
Here's your answer
Given,
To factorise x² - y² + 2x + 1
Regrouping the terms,
we have ,
x² + 2x + 1 - y²
Using the identity (x+y)²=x² + 2xy + y²,
we have,
(x)² + 2(x)(1) + 1² - y²
(x + 1)² - y²
Using the identity , a² - b² = (a - b)(a + b)
x² - y² + 2x + 1 = (x + 1 - y)(x + 1 + y) [ Answer. ]
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Answered by
51
here is your ans mark as brainlyiest
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