Question

factorise the following using suitable identities X square + 4 y square + z square - 4xy - 4yz + 2zx​

Answer 1

Answer:

${x}^{2} + 4 {y}^{2} + {z}^{2} - 4xy - 4yz + 2zx \\ \\ (x)^{2} + {( - 2y)}^{2} + {(z)}^{2} + 2( - 2y)(x) + 2( - 2y)(z) + 2(z)(x) \\ \\ (x - 2y + z)^{2}$

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