Question

factorise the following using suitable indentities x^2 - 2x + 1​

Answer 1

Identity -

$</strong><strong> </strong><strong>{(</strong><strong>a</strong><strong>- </strong><strong>b</strong><strong>)}^{2} </strong><strong>=</strong><strong>({</strong><strong>a</strong><strong>})^{2}</strong><strong>+ {(</strong><strong>b</strong><strong>)}^{2}</strong><strong>- 2</strong><strong>a</strong><strong>b</strong><strong> </strong><strong>$

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${x}^{2} - 2x + 1 \\ = ({x})^{2} - 2 \times x \times 1 + {(1)}^{2} \\ = {(x - 1)}^{2}$

Answer 2

Answer:

it is (x-1)²

Step-by-step explanation:

Check the picture.

Answer will be (x-1) ²

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