Factorise the following, using the identity (ii) 28ay2
-175ax2
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28ay^2 - 175ax^2
= 7a (4y^2 - 25x^2)
= 7a {(2y)^2 - (5x)^2}
As we know that (a^2 - b^2) = (a + b) X (a - b)
So,
28ay^2 - 175ax^2
= 7a X (2y + 5x) X (2y - 5x)
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1
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