Question

Factorise the following with identies 1+a+ab+a2b

Answer 1

Answer:

1 = 1 (no more variables r found)

a = a (no more variables found)

ab = a× b

a2b = a × a × b

by grouping method

(a + 1) (a + a2b)

(a + 1) a(ab)

hope this helps you.... if yes then please mark me the brainliest

Answer 2

Given:

An expression $1+a+ab+a^2b$.

To Find:

To factorize the expression $1+a+ab+a^2b$.

Solution:

Group the terms $1+a$ together and $ab+a^2b$ together in the expression $1+a+ab+a^2b$.

$1+a+ab+a^2b=(1+a)+(ab+a^2b)$

Take out 'a' and 'b' as a common factor from the second bracket.

$(1+a)+ab(1+a)$

Take out $1+a$ as a common factor from the whole expression.

$(1+a)+ab(1+a)=(1+a)(1+ab)$

Thus, $(1+a)(1+ab)$ is obtained after factorizing $1+a+ab+a^2b$.