factorise the following x^2+6x+8
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Given that: x² + 6x + 8
=x² + 4x + 2x + 8, (split middle term)
=(x² + 4x) + (2x + 8),(group pair of terms)
8),(group pair of terms) =x(x+4)+2(x+4),(factor each binomials)
8),(group pair of terms) =x(x+4)+2(x+4),(factor each binomials) =(x+4)(x+2),(factor out common factor (x+4)
8),(group pair of terms) =x(x+4)+2(x+4),(factor each binomials) =(x+4)(x+2),(factor out common factor (x+4)Hence factors of x²+6x+8 are (x+4)(x+2)
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