Question

factorise the following
x^2+7x-60

Answer 1

Answer:

The values of $x = 12$ and $-5$

Step-by-step explanation:

The given quadratic equation is, $x^{2} + 7x - 60$

To find : The value of $x$.

Solution :  

• The given quadratic equation is $x^{2} + 7x - 60$
• To solve this equation, we have to split the last constant term coefficient,  into two factors in such a way that whose product will be  and addition or subtraction of that two terms will be .
• ∴ $x^{2} + 12x - 5x -60 = 0$

• Taking out common terms,

 ∴ $x(x-12) + 5(x-12) = 0$

          ∴ $(x-12) (x+5) = 0$

• ∴ Equating with zero, we get

          ∴$(x - 12) = 0 , (x+5)=0$

                ∴ $x= 12 , x = -5$

• ∴ The values of $x$ is $12, -5$.

Answer 2

Given equation is $x^{2} +7x-60$

Here we have to find the value of $x$

As the highest power of $x$ in the given equation is $2$.

So, there exists two $'x'$ values.

For this we have to split the equation.

We get,

$x^{2} +12x-5x-60=0$

$x(x+12)-5(x+12)=0$

From the above take $(x+12)$ common.

We get,

$(x+12)(x-5)=0$

Equate both the terms with zero.

We get,

$(x+12)=0;(x-5)=0$

$x=-12;x=5$

Therefore, the values of $x$ are $-12,5$