FACTORISE THE FOLLOWING:
x^3+3x^2+3x-7
Answers
Answer:
(x - 1 ) (x^2 + 4x +7)
Step-by-step explanation:
P(x) = x^3+3x^2+3x-7
P(1) = 1 + 3 + 3 -7 =7- 7 = 0
(x - 1 ) is a factor
x -1 ) x^3+3x^2+3x-7( x^2 + 4x +7
x^3-x^2
4x^2 + 3x
4x^2 - 4x
7x - 7
7x - 7
0
(x - 1 ) (x^2 + 4x +7)
Answer:
(x - 2)(x² + 4x + 7)
Step-by-step explanation:
BY REMAINDER THEOREM,
P(x) = x³+3x²+3x-7
P(1) = 1+3+3-7
= 7-7
= 0
* (x - 1) is a factor.
BY LONG DIVISION METHOD,
x-1 )x³+3x²+3x-7(x²+4x+7
x³ - x²
4x² +3x
4x² - 4x
7x-7
7x-7
0
(x²+4x+7) is another factor.
So, (x - 1) & (x²+4x+7) are the factors of x³+3x²+3x-7.
Hope I helped U.