Question

factorise the following x square - 4 x minus 5​

Answer 1

$\huge\boxed{\fcolorbox{cyan}{grey}{Solution:-}}$

$\sf x{}^{2}-4x-5 \\ \sf\implies x{}^{2}-(5-1)x-5 \\ \sf\implies x{}^{2}-5x+x-5 \\ \sf\implies x(x-5)+1(x-5) \\ \sf\implies (x-5)(x+1) \\ \sf The\: value\:of\:x\:is \\ \sf x-5=0\\ \sf x=5 \\ \sf x+1=0 \\ \sf x=-1 \\ \sf The\: value\:of\:x\:is (5 )and (-1)$

Answer 2

Answer:

Hey mate I will help

Step-by-step explanation:

${x}^{2} - 4x - 5 \\ by \: using \: middle \: term \: spliting \: methods \\ \\ {x}^{2} - 5x - x - 5$

$x(x - 5) + 1(x - 5) = 0 \\ (x - 5) = 0 \: or \: (x + 1) = 0 \\ x = 5 \: and \: x = - 1$