Question

factorise the following x square+6squre -16 by factorization method​

Answer 1

$\bold\red{\underline{\underline{Answer:}}}$

$\bold{(x-2)(x+8)}$

$\bold\orange{Given:}$

$\bold{The \ given \ quadratic \ polynomial \ is }$

$\bold{x^{2}+6x-16}$

$\bold\blue{Explanation}$

$\bold{The \ given \ quadratic \ polynomial \ is }$

$\bold{x^{2}+6x-16}$

$\bold{Here, \ a=1, \ b=6 \ and \ c=-16}$

$\bold{a×c=1×(-16)=-16}$

$\bold{For \ factorisation \ we \ should \ split}$

$\bold{middle \ term \ such \ that \ it's \ product}$

$\bold{is \ -16 \ and \ sum \ is \ 6.}$

$\bold\green{\underline{\underline{Solution}}}$

$\bold{The \ given \ quadratic \ polynomial \ is }$

$\bold{=>x^{2}+6x-16}$

$\bold{=>x^{2}-2x+8x+16}$

$\bold{=>x(x-2)+8(x-2)}$

$\bold{=>(x-2)(x+8)}$

Answer 2

Aɴsᴡᴇʀ :-

The given quadratic polynomial is

x² + 6 - 16

here a = 1 , b = 6 , c = - 16

a × c = 1 × ( - 16 ) = - 16

For factorisation we should split middle term such that it's product is -16 and sum is 6

= = > x² + 8x - 2x - 16

= = > x ( x + 8 ) - 2 ( x + 8 )

= = > ( x - 2 ) ( x + 8 )

Hᴏᴘᴇ ɪᴛ ʜᴇʟᴘs..!