Question

factorise the following x square+6squre -16 by factorization method​

Answer 1

CORRECt QUESTIOn

x² + 6x - 16

Factories it

SOLUTIOn

→ x² + 6x - 16

Solve it by splitting middle term

→ x² + 8x - 2x - 16

→ x(x + 8) - 2(x + 8)

→ (x + 8)(x - 2)

SOMe IDENTITIEs

• (a + b)² = a² + b² + 2ab
• (a - b)² = a² + b² - 2ab
• a² - b² = (a + b)(a - b)

Answer 2

AnsWer :

x = 2 and - 8.

Solution :

We have,

$\rule{90}3$

Let Apply factorization method.

=> x² + 6x - 16

=> x² + 8x - 2x - 16.

=> x( x + 8 ) - 2 ( x + 8 )

=> ( x - 2 ) ( x + 8 )

$\rule{90}3$

Let Solve my Other method ( Quadratic Formula )

$\tt \dagger \: \: \: \: \: x = \dfrac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a}$

Where as,

• a = 1.
• b = 6.
• c = - 16.

$\tt : \implies x = \dfrac{ - 6 \pm \sqrt{ {(6)}^{2} - 4 \times 1 \times - 16} }{2}$

$\tt:\implies x = \dfrac{ - 6 \pm \sqrt{36 + 64} }{2}$

$\tt :\implies x = \dfrac{ - 6 \pm \sqrt{100} }{2}$

$\tt: \implies x = \dfrac{ - 6 \pm 10}{2}$

Either,

$\tt :\implies x = \dfrac{ - 6 + 10 }{2}$

$\tt: \implies x = \dfrac{ 4 }{2}$

$\tt :\implies x = 2 .$

Or,

$\tt: \implies x = \dfrac{ - 6 - 10 }{2}$

$\tt :\implies x = \dfrac{ - 16 }{2}$

$\tt: \implies x = - 8.$

Therefore, the value of x is 2 and - 8.