Math, asked by EramAnjum, 5 months ago

Factorise the following:
x(x+y)^3-3x^2y(x+y)​

Answers

Answered by Anonymous
2

 =  > x {(x + y)}^{3}  - 3 {x}^{2}y(x + y) \\  =  > x {(x + y)}^{2}(x + y)  - 3 {x}^{2}y(x + y)  \\ =  > (x + y)(x {(x + y)}^{2} - 3 {x}^{2}y) \\  =  > (x + y)(x( {x}^{2}  +  {y}^{2}  + 2xy) - 3 {x}^{2}y) \\  =  > (x + y)( ({x}^{3}   +  x{y}^{2}  + 2 {x}^{2} y) - 3 {x}^{2}y) \\  =  > (x + y)( {x}^{3}   +  x{y}^{2}  + 2 {x}^{2} y - 3 {x}^{2}y) \\  =  > (x + y)( {x}^{3}   +  x{y}^{2}  -  {x}^{2}y)

Hope it's helpful to you

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