Question

factorise the following x²+6x+9 and x²+2x-15 and 49a²+70ab+25b² and 25x²-49y² and x²+6x+9​

Answer 1

Step-by-step explanation:

i)x²+6x+9=0

x²+(3+3)x+9=0

x²+3x+3x+9=0

x(x+3)+3(x+3)=0

(x+3)(x+3)=0

ii)x²+2x-15=0

x²+(5-3)x-15=0

x²+5x-3x-15=0

x(x+5)-3(x+5)=0

(x+5)(x-3)=0

iii)49a²+70ab+25b²=0

49a²+(35+35)ab+25b²=0

49a²+35ab+35ab+25b²=0

7a(7a+5b)+5b(7a+5b)=0

(7a+5b)(7a+5b)=0

iv)25x²-49y²=0

(5x)²-(7y)²=0

(5x+7y)(5x-7y)=0{a²-b²=(a+b)(a-b)}