Question

Factorise the following
: x⁸-y⁸

Answer 1

Answer:

Below

Step-by-step explanation:

Tjis uses the identity ---- a3 - b3 = ( a - b ) ( a2 - ab -b2 )

x8 -y8 = ( x2 -y2 ) ( x4 - x2y2 -y4 ) [ To understand this better we will take a as x2 because x2's cube is x8 and . b as y8because y2's cube is y8 ]

HOPE THIS HELPS

Answer 2

x⁸-y⁸ = ( x⁴)² - ( y⁴)²

= (x⁴+y⁴) (x⁴-y⁴) [ Using identity a²-b² = (a+b) (a-b)]

= (x⁴+y⁴) [(x²)² - (y²)²]

= (x⁴+y⁴) (x²+y²) (x²-y²)

= (x⁴+y⁴) (x²+y²) (x+y) (x-y) ⇒ Answer

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