factorise the following x⁹ + y⁹
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Let's break it down first. Using properties of exponents, I can rewrite this as:
x9+y9=(x3)3+(y3)3
The reason I rewrote this like this is because I know how to factor the sum of cubes:
u=x3
v=y3
So, now I just factor the following:
u3+v3=(u+v)(u2−uv+v2)
Now, plug x and y back in:
(x3+y3)((x3)2−(xy)3+(y3)2)
Then we can factor the first factor again:
((x+y)(x2−xy+y2))((x3)2−(xy)3+(y3)2)
=(x+y)(x2−xy+y2)(x6−x3y3+y6)
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xy 18 this is a simple answer mark me as a Brainlist
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