Question

factorise the following xcube-2x square+3x-2​

Answer 1

Answer:

${x}^{?3 } - 2 { {x}^{2} }^{?} + 3x - 2 \\ x {}^{2} (x - 2) + 3(x - 2) \\ (x - 2)(x {?}^{2} + 3)$

Answer 2

Answer:

p=-14/3

Step-by-step explanation:

The zero of 3x-2is 2/3

Since 3x-2 is a factor

3x cube +2x square+ px+2=0

3x2/3 cube +2x2/3 square+p2/3+2=0

2/9+8/9+p2/3+2=0

Taking L.C.M of 9,9,3,we get as 9

2+8+6p+18 whole divided by 9=0

Multiplying 9and 0 we get 0

Again carrying 6p in the R.H.S we get -6p

And adding 2,8,18 we get 28

28=-6p

p=28/-6

p=-14/3