Factorise the following: y3+y2-y-1
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dixitsanskar5286
18.07.2018
Math
Secondary School
+15 pts
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Factorise the following: y3+y2-y-1
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rakeshmohata
rakeshmohata Ace
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= > {y}^{3} + {y}^{2} - y - 1 \\ \\ = {y}^{2} (y + 1) - 1(y + 1) \\ \\ = (y + 1)( {y}^{2} - 1) \\ \\ = (y + 1)(y - 1)(y + 1) \\ \\ = (y - 1)(y + 1) ^{2}
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ColinJacobus Ambitious
Answer: The required factored form of the given expression is (y+1)(y+1)(y-1).
Step-by-step explanation: We are given to factorize the following cubic expression :
E=y^3+y^2-y-1~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)
We will be using the following formula :
a^2-b^2=(a+b)(a-b).
The factorization of the given expression (i) is as follows :
E\\\\=y^3+y^2-y-1\\\\=y^2(y+1)-1(y+1)\\\\=(y+1)(y^2-1)\\\\=(y+1)(y^2-1^2)\\\\=(y+1)(y+1)(y-1).
Thus, the required factored form of the given expression is (y+1)(y+1)(y-1).
Answer:
y =1/4
Step-by-step explanation:
3y+2y-y-1=0
5y-y=1
4y=1
y=1/4