Question

factorise the following. z²+9z+20 ​

Answer 1

Step-by-step explanation:

z²+5z+4z+20

z(z+5)+4(z+5)

(z+5)(z+4)

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Answer 2

Answer:

We will factorize it in such a way that the 2 middle numbers sum will be 9z and product will be 20z²

Therefore, it is clear that such numbers will be 4z and 5z so that their sum is also 9z and product is also 20z²...

Factorization -

z² + 9z + 20

Now we will split the middle term by the numbers we found above.

= z² + 4z + 5z + 20

Now, take common.

= z² + 4z + 5z + 20

= z(z+4) + 5(z+4)

= ( z+4 )( z+5 )

Therefore, your answer is ( z+4 )( z+5 )

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