Question

Factorise the followings

•) 3abc(4- 2abc + a²b²c²)
•) 2mn² + 2n²P + m + 4np + 4mn + p
•) 48m⁴ - 3​

Answer 1

Answer:

1.)  3abc(4-2abc+a²b²c²)

   = 3a²b²c²(4-2+abc)

   = 6a²b²c²[2(2-1)+abc]

2.)   2mn² + 2n²p + m + 4np + 4mn + p

   = (2mn² + 2n²p) + (m + p) + (4np + 4mn)

    = 2n²(m + p) + 1(m + p) + 4n(p + m)

    = (m + p)(2n² + 1 + 4n)

    = (m + p)(2n² + 4n + 1)

3.)   48m⁴ - 3

    = 3(16m⁴-1)

    = 3[(4m²)² -1²]

    = 3[(4m²+1)(4m²-1)]     {By identity a²- b²= (a+b)(a-b)}