Question

factorise the given 64a³-b³​

Answer 1

Answer:

64a³-b³ = (4a)³ -(b)³ )

now , we know that

(a³-b³) = (a-b)(a²+b²+ab)

so,

(4a)³ -(b)³ = (4a-b)(16a²+b²+4ab) (Ans)

Answer 2

Answer:

a 3-b3=(a-b)(a^2+ab+ b^2)

64a^3-b^3=(4a-b)(16a^2+4ab+b^2)

factors = (4a-b), (16a^2+4ab+b^2)