Factorise the given algebraic expression. (2x-3y)² -6x+9y
Answers
Answer
12(2x – 3y)2 – 16(3y – 2x)
= 12(2x – 3y)2 + 16(2x -3y)
[Taking (2x - 3y) common from the expression]
= (2x – 3y) {12(2x – 3y) + 16}
= (2x – 3y)(24x – 36y + 16)
[Taking 4 common from the expression]
= 4(2x - 3y)(6x – 9y + 4)
So,
We get,
12(2x – 3y)2 – 16(3y – 2x) = 4(2x - 3y)(6x – 9y + 4)
Step-by-step explanation:
make me Brainlist
Answer:
Register
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
Q. 15
4.2
( 46 Votes )
<span lang="EN-US
Class 8th
RS Aggarwal - Mathematics
7. Factorisation
Answer
12(2x – 3y)2 – 16(3y – 2x)
= 12(2x – 3y)2 + 16(2x -3y)
[Taking (2x - 3y) common from the expression]
= (2x – 3y) {12(2x – 3y) + 16}
= (2x – 3y)(24x – 36y + 16)
[Taking 4 common from the expression]
= 4(2x - 3y)(6x – 9y + 4)
So,
We get,
12(2x – 3y)2 – 16(3y – 2x) = 4(2x - 3y)(6x – 9y + 4)